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January 27, 2015

January 27, 2015

Posted by **Anonymous** on Tuesday, December 8, 2009 at 9:01pm.

- Math -
**drwls**, Tuesday, December 8, 2009 at 9:31pmDuring 0 <t < 0.25 h, y = 4t and x = 0

R = Distance from starting point = y

During 0.25 < t < 5.75 h, y = 4 and x = 4(t-0.25)

R = sqrt(x^2 + y^2)

You do the last leg. That should give you the idea

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