Posted by **jackie** on Tuesday, December 8, 2009 at 6:26pm.

find the derivative of f(x)=cot(3x)csc^2(3x)

- calculus -
**drwls**, Tuesday, December 8, 2009 at 6:33pm
f(x)=cot(3x)csc^2(3x) = cosx/sin^3x

Let sinx = u . Then du = cosx dx

The integral of f(x) becomes

Integral of du/u^3 = -(1/2) u^-2

= (-1/2)(1/sinx)^2

= (-1/2)csc^2x

- calculus -
**Reiny**, Tuesday, December 8, 2009 at 7:45pm
first change it to

f(x) = cos 3x/(sin 3x)^3 like drwls had

now use the quotient rule to find f'(x)

f'(x) = [(sin 3x)^3(-3)(sin 3x) - 3(sin 3x)^2(cos 3x)(3)(cos 3x)]/(sin 3x)^6

= -3[(sin 3x)^2 + 3(cos 3x)^2]/(sin 3x)^4

- calculus -
**drwls**, Tuesday, December 8, 2009 at 9:47pm
I made at least one mistake. The first was using x instead of 3x.

## Answer this Question

## Related Questions

- Calculus - Find the derivative of y=cot³(1-2x)² y'=3[cot(1-2x)²]² (-csc²(1-2x...
- Calculus - Any help would be much appreciated with the steps involved in each ...
- Calculus - Any help would be much appreciated with the steps involved in each ...
- Trig verifying identities - I am having trouble with this problem. sec^2(pi/2-x...
- Chain Rule - Any help would be much appreciated with the steps involved in each ...
- Trigonometry - Hello all, In our math class, we are practicing the trigonometric...
- Calculus - Hello, I'm having trouble with this exercise. Can you help me? ...
- Calculus - yes! tnk u ok? It's actually (x->0.) Find the limit of cot(x)-csc(...
- Math - Trig - I'm trying to verify these trigonometric identities. 1. 1 / [sec(x...
- calculus - We're doing indefinite integrals using the substitution rule right ...