Wednesday

April 23, 2014

April 23, 2014

Posted by **Victoria** on Tuesday, December 8, 2009 at 5:53pm.

7 pi/6. I subtracted 2 pi from this and got -5pi/6. But the correct answer is pi/6. Whwere did this come from?

- Trig -
**MathMate**, Tuesday, December 8, 2009 at 6:14pmIf you are referring to reference angles, it is the acute angle that makes with the x-axis.

Since it is either 0 or 2π for the positive x-axis, or π for the negative x-axis, 7pi/6 makes π/6 with the negative x-axis, therefore the answer would be &pi/6.

If the question is not about reference angles, then you need to elaborate a little more.

- Trig -
**Christopher M. Boan**, Tuesday, December 8, 2009 at 7:01pmWell in short pie means 180 degrees or 3.14 radians... subtracting 2 pie would be subtracting 360 giving you a co-terminal angle here's how i would've worked the problem

5pie 180 = 150 degrees

6 * pie

that's 30 degrees away from pie or 180

30 2pie = 1pie

pie * 180 6

in short 30 degrees equals 1pie over 6 and that's how far your angle is away from 180 or pie

- Trig -
**Christopher M. Boan**, Tuesday, December 8, 2009 at 7:05pmthe way it posted looks bad so I'm redoing the math with slash signs

5pie/6 * 180/pie = 150

30/pie * 2pie/180 = 1pie/6

**Related Questions**

Math - Solve (sinx-1)(cosx -1/2) = 0 where 0≤x<2pi a) pi/3, pi/2, 5pi/3...

Trig. - Why is the arctan of (- square root of 3) 5 pi/6. How come it isn't ...

Advanced Math - Find the values of x for which the equation sin x = -1 is true 2...

Pre-Cal(Please check) - Approximate the equation's solutions in the interval (0,...

Calculus - The problem with these two questions is that I cannot determine the a...

trig - Solve the equation for cos theta-tan theta=0 for greater than or egual to...

Math(Please help) - 1)tan Q = -3/4 Find cosQ -3^2 + 4^2 = x^2 9+16 = sqrt 25 = 5...

Math - Trig - For the equation 4 cos theta - square root 12 = 0, where 0 < ...

***Discrete Math***, pi^2. - In S(5), let pi=(245)(1354)(125). (a) Write pi as a...

Linear Algebra - Hello, I'm trying to find the Fourier Series of a function ...