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April 1, 2015

April 1, 2015

Posted by **Salman** on Tuesday, December 8, 2009 at 2:19pm.

- Math -
**drwls**, Tuesday, December 8, 2009 at 4:31pmLet e^5x = u

Then

5 e^5x dx = du

The integral becomes

INT (1/5)u/[u^2 +4] du

Now let v = u^2 + 4

dv = 2u du

The integral becomes

(1/10) INT (1/v)dv

= (1/10)ln v = (1/10) ln(u^2 + 4)

= (1/10)ln(e^10x + 4)

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