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My brain refuses to wrap around titration. Problem: Given 150.0 mL of a 1.05 M HCl solution, how many milliliters of a 2.50 M Al(OH)3 solution are required to neutralize the HCl?

I think the balanced formula is 3HCl + Al(OH)3 - AlCl +3H20 but that's as far as I get.

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