A force of 400.0N is exerted on a 1,250N car while moving it a distance of 3.0m. How much work is done on the car.
Is there a technological device that doesn't convert one form of energy into another.
I think alan is on the right track. but its 1200 J
To calculate the work done on the car, we can use the formula:
Work = Force * Distance * cos(theta)
Where:
- Work is the amount of work done (in joules)
- Force is the applied force on the car (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the direction of the force and the direction of the displacement (typically considered to be 0 degrees).
In this case, the force (F) is 400.0N, the distance (d) is 3.0m, and theta is 0 degrees (since the force is applied in the same direction as the displacement). Therefore, we can substitute these values into the formula:
Work = 400.0N * 3.0m * cos(0 degrees)
Since cos(0 degrees) = 1, the equation simplifies to:
Work = 400.0N * 3.0m * 1
Work = 1200.0 joules
So, 1200.0 joules of work is done on the car.
W=FD
W=(400N)(3.0m)
W=1200N
I don't really get the 1250N car thing. Unless you also need friction, but i need the coefficent for that.