Posted by Becca on Monday, December 7, 2009 at 8:41pm.
1. Write equations for distance traveled vs. the time after 11 AM. Set them equal and solve for t.
M = .5 t (if t is in minutes)
L = .6 (t -20)
M = L when 0.5t = 0.6t -12
0.1t = 12
t = 120 minutes (after 11 AM), which is 1:00 PM
2. Assume X liters of 10/90 mix are added
Liters of acid in mix = 0.1X + 5
Liters of water in mix = 0.9X
Total volume of mix = 5 + X
Solve 0.4 = 0.9X/(5+X)
2 + 0.4X = 0.9X
X = 4
90% of X is the amount of water
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