Tuesday

November 25, 2014

November 25, 2014

Posted by **Nelson** on Monday, December 7, 2009 at 3:07pm.

- Algebra -
**Reiny**, Monday, December 7, 2009 at 3:15pmlet the two numbers be x and x+1

then x(x+1) = x + y + 41

expanding and simplifying we get

x^2 - x - 42 = 0

(x-7)(x+6) = 0

x = 7 or x = -6

case 1: the two numbers are 7 and 8

check: product = 56

sum = 15, 56 is greater than 15 by 41

case 2: the two numbers are -6 and -5

check: product is 30

sum is -11

30 is 41 greater than -11

so the two numbers are either 7 and 8 or

-6 and -5

**Answer this Question**

**Related Questions**

math - i dont get this question consecutive integers are integers that differ by...

Algebra - The difference of the cubes of two consecutive odd positive integers ...

Algebra - The difference of the cubes of two consecutive odd positive integers ...

algebra! - The difference of the cubes of two consecutive odd positive integers ...

Algebra - The difference of the cubes of two consecutive odd positive integers ...

math - The product of two consecutive positive integers is 11 more than their ...

Amanda - The product of two consecutive positive integers is 11 more than their ...

Math - When you solve questions like "The sum of 3 consecutive integers is 147. ...

math, algebra - 2a+2ab+2b I need a lot of help in this one. it says find two ...

algebra - The sum of the squares of two consecutive odd integers decreased by ...