A car weighing 1.1*10^4 N is parked on a 35 degree slope.
Find the force tending to cause the car to roll down the hill.
What is the force the car exerts perpendicular to the hill?
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To find the force tending to cause the car to roll down the hill, we need to consider the component of the weight of the car that is acting parallel to the slope. This component will be responsible for causing the car to move downwards.
The weight of the car is given as 1.1*10^4 N, which is the force acting vertically downwards. To find the force parallel to the slope, we need to determine the component of the weight acting in that direction. This can be done using trigonometry.
Since the slope angle is 35 degrees, the component of the weight acting parallel to the slope is given by:
Force parallel = Weight * sin(angle)
Force parallel = (1.1*10^4 N) * sin(35 degrees)
Calculating this value will give us the force tending to cause the car to roll down the hill.
To find the force the car exerts perpendicular to the hill, we need to consider the component of the weight of the car that is acting perpendicular to the slope. This component will be responsible for keeping the car stationary on the slope.
The force perpendicular to the hill can be calculated using a similar approach. We will use trigonometry again, but this time we will use the cosine function to find the component of the weight acting perpendicular to the slope.
Force perpendicular = Weight * cos(angle)
Force perpendicular = (1.1*10^4 N) * cos(35 degrees)
Calculating this value will give us the force the car exerts perpendicular to the hill.