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November 28, 2014

November 28, 2014

Posted by **Brian** on Monday, December 7, 2009 at 12:32am.

How do I do this?

- math/probability -
**Reiny**, Monday, December 7, 2009 at 8:54amlet A be "sum of 6" and B be "double"

What you have is P(A│B) , read as

the probability of A given B

which is defined as P(A AND B)/P(B)

Prob(A AND B) = Prob(sum of 6 AND a double) = 1/36

Prob(B) = 6/36 = 1/6

so Prob(sum of 6 AND a double) = (1/36)÷(1/6)

= (1/36)(6/1) = 1/6

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