f'(x) = lnx*6*e^(-5x)*(-5) + (6/x)e^(-5x) = e^(-5x)[-30 lnx + (6/x)] Plug in x = 3 to get f'(3) e^-15 = 3.059*10^-7 -30 lnx = -32.96 6/x = 2
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