Monday

September 22, 2014

September 22, 2014

Posted by **Jenna** on Sunday, December 6, 2009 at 10:08pm.

(integral of) 2y^4dy/y^3 - y^2 + y - 1

After long divison I get:

(integral of)2ydy + 2(integral of)dy + (integral of) 2/y^3 - y^2 + y - 1

I keep getting stuck here. I can't write this as a sum of partial fractions because I can't figure out how to rearrange the denominator so that I CAN write it as a sum o partial fractions. Any ideas?

- Calc II -
**Reiny**, Sunday, December 6, 2009 at 10:48pmYou can factor

y^3 - y^2 + y - 1

= y^2(y-1) + (y-1)

= (y-1)(y^2 + 1)

**Answer this Question**

**Related Questions**

calc II - Express the integrals as the sum of partial fractions and evaluate the...

Cal II - express integrand as sum of partial fractions and evaluate the integral...

calculus - evaluate integral or state that it is diverges integral -oo, -2 [2/(x...

calculus - find the exact length of the curve y = ln(1-x^2), 0 <= x <= (1/...

Calc - integral (x^3)/(x^2-2x+1) from -1 to 0 How do you get this integral? I ...

Calc Help Please Again Last one! - Write out the form of the partial fraction ...

Calc easy - Having trouble getting the correct solution. The integral of “x ...

Calc - (1/1+(4/n))(4/n)+(1/1+(8/n))(4/n)+(1/1+(12/n))(4/n)+....+(1/1+(4n/n))(4/n...

calculus - 1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta...

Math - Use FTC to evaluate a definite integral with basic integrand-- (integral...