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January 27, 2015

January 27, 2015

Posted by **Jenna** on Sunday, December 6, 2009 at 10:08pm.

(integral of) 2y^4dy/y^3 - y^2 + y - 1

After long divison I get:

(integral of)2ydy + 2(integral of)dy + (integral of) 2/y^3 - y^2 + y - 1

I keep getting stuck here. I can't write this as a sum of partial fractions because I can't figure out how to rearrange the denominator so that I CAN write it as a sum o partial fractions. Any ideas?

- Calc II -
**Reiny**, Sunday, December 6, 2009 at 10:48pmYou can factor

y^3 - y^2 + y - 1

= y^2(y-1) + (y-1)

= (y-1)(y^2 + 1)

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