Posted by AE on Sunday, December 6, 2009 at 5:48pm.
The net rate of radiative power loss is
(Area)*sigma* [T(body)^4 - T(room)^4]
The radiation is almost entirely invisible infrared.
When using the formula, T must be in Kelvin and the "sigma" is the Stefan-Boltzmann constant, which must be explained in your tesxt somewhefre. Look it up.
The negative room temperature term takes into account the radiation of the room onto the body.
I did that but the website that I do the homework on says my answer is wrong. Here are the numbers I plugged in:
(1.9 )(5.67*10^8)((31+273)^4 - (19+273)^4)
and I get the answer is 1.37*10^18 but it says that's wrong
oh, never mind, I got it, I was using the wrong value for the constant, thanks!
Related Questions
Health - I posted this question yesterday and I got confused. The determinant of...
Health - Can you help me with this question? The determinant of total energy ...
physics - A weightlifter has a basal metabolic rate of 80.0 W. As he is working ...
physics - The basal metabolic rate is the rate at which energy is produced in ...
Physics - A person's body is producing energy internally due to metabolic ...
Physics - Overall 80 % of the energy used by the body must be eliminated as ...
physics - A person's body is producing energy internally due to metabolic ...
Chemistry(please help) - I have to calculate the concentration of I2 produced...
Calculus - According to Kleiber's Law, the metabolic rate P (in kilocalories...
Calculus - According to Kleiber's Law, the metabolic rate P (in kilocalories...
For Further Reading