Posted by **Anonymous** on Saturday, December 5, 2009 at 9:14pm.

A sports car of mass 1400 kg (including the driver) crosses the rounded top of a hill (radius = 93 m) at 27 m/s.

1) Determine the normal force exerted by the road on the car.

2) Determine the normal force exerted by the car on the 75 kg driver.

3) Determine the car speed at which the normal force on the driver equals zero.

- Physics -
**bobpursley**, Saturday, December 5, 2009 at 9:43pm
I will be happy to critique your thinking.

- Physics -
**Anonymous**, Saturday, December 5, 2009 at 9:48pm
I can't seem to get past the first question. I tried squaring the velocity, dividing that by the radius, and then multiplying all of that by the weight of the car. That answer wasn't right.

- Physics -
**bobpursley**, Saturday, December 5, 2009 at 9:52pm
Of course it isn't right. Why did you multiply centripetal acceleration by a force?

It idea is to look at the net force downward by the car.

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