PhysicsPLEASE ANSWER, it's due soon!
posted by AE on .
A copper calorimeter can with mass 0.202 kg contains 0.185 kg of water and 1.40×10^−2 kg of ice in thermal equilibrium at atmospheric pressure. If 0.900 kg of lead at a temperature of 417 degrees celsius is dropped into the can, what is the final temperature of the system if no heat is lost to the surroundings?

The sum of the heats gained is zero (some will be negative, as in heat lost).
heat gained calorimeter=masscalor*ccu*(Tf273)
heat gained by water= (masswater+massmelted ice)*cw*(tf0)
heat gained by ice= Hf(massice)
Heat gained by lead=masslead*clead*(tf(417+273))
add all these, set to zero, and solve for Tf. 
I'm putting in the answer I get but the website that I do the homework on says the answer is wrong. I'm getting 94.77 K for final temperature, but it says that's wrong. What should I do?

I would recheck it. You know it cant be 94Kelvin. That is pretty cold.