Posted by O_o Rion on Saturday, December 5, 2009 at 8:31pm.
In an integration solution, the integral of (1/(sqrt (8-u squared)) is written as arcsin(u/sqrt 8), but I dont see how they got it. When I did it I got (1/8)*(arcsin(u*sqrt8)). What I did was take sqrt8 common in the denominator to get it in the form sqrt(1-u sq.) and then find the integral (arcsin u) and then since my 'u' was sqrt.8 * u, I divided sqrt.8 from the whole thing. Where did I go wrong?
- Calculus - MathMate, Sunday, December 6, 2009 at 9:20am
"take sqrt8 common in the denominator to get it in the form sqrt(1-u sq.)"
Shouldn't it be
When you do a substitution, it is always advisable to use a different letter. You are likely to confuse yourself if you use the same letter, namely, substitute u by u/sqrt(8).
- Calculus - Laurie, Thursday, May 24, 2012 at 12:44pm
square root of (1-u squared)
Answer this Question
More Related Questions
- calculus - How do you find: the Integral of arcsin(1 / (sqrt x^2 - 1) ) dx ?? (...
- calculus-integration! - should i use substitution?? if yes how should should i ...
- Calculus - Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of...
- Calculus - Book works out integral of sqtr(a^2-x^2)dx as a^2/2*arcsin(x/a)+x/2*...
- Calculus - Evaluate the indefinite integral: 8x-x^2. I got this but I the ...
- Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...
- Math Help please!! - Could someone show me how to solve these problems step by ...
- Calculus AP - hi again im really need help TextBook: James Stewart:Essential ...
- Trigonometry - I need help with I just can't seem to get anywhere. this is as ...
- calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...