Posted by **Janet** on Saturday, December 5, 2009 at 7:58pm.

At the first tri-city meeting, there are 8 people from town A, 7 people from town B, and 5 people from town C. If a council consisting of 5 people is randomly selected, find the probability that 3 are from town A and 2 are from town B.

- math help -
**Reiny**, Saturday, December 5, 2009 at 8:21pm
Without restrictions, number of councils is

C(20,5) or 15504

I will assume you want exactly 3 from A and 2 from B, so that number is C(8,3)xC(7,2) or 1176

so prob(of stated event) = 1176/15504

= 49/646 or .07585

## Answer this Question

## Related Questions

- Math - At the first tri-city meeting, there are 8 people from town A, 7 people ...
- Math - At the first tri-city meeting, there are 8 people from town A, 7 people ...
- math - At the first tri-city meeting there are 8 people from town A, 7 people ...
- algebra - At the first tri-city meeting, there are 8 people from town A, 7 ...
- Math- Still Don't Understand! - I do not understand how to work this problem out...
- math 157 - at the first tri city meeting where 8 people are from twon A 7 people...
- math 157 - at the first tri city meeting where 8 people are from twon A 7 people...
- Math - Please Help Me! - How many ways can an IRS auditor select 3 of 11 tax ...
- Math Word Problems - How many ways can an IRS auditor select 3 of 11 tax returns...
- math - In a certain town, 25% of people commute to work by bicycle. If a person ...

More Related Questions