Posted by Ashley on Saturday, December 5, 2009 at 7:01pm.
The auditor chooses the first return out of 11, that makes 11 choices. For the second, she is left with 10, so there are 11*10 ways. For the third, she has 9 returns left from which to choose, so there are 11*10*9=990 ways to choosing the first 3 returns.
However, out of the 990 ways to choose the returns, each combination (say A,B,C) would have been repeated in 6 different orders, like ABC, BAC, CAB, BCA, ACB, CBA. The number of repetitions can be calculated by 6=3!, where three is the number of returns chosen.
Thus the number of ways she can choose 3 returns would be
11*10*9/3!=990/6=165.
It's your turn to choose the sub-committees and try the rest of the exercises.
If you have difficulties, post what you have or what the difficulties are.
i need help me on math
like 2+2=
Related Questions
math - how many ways can an IRS auditor select 3 of 11 tax returns for an audit...
math - How many ways can an IRS auditor select 4 of 8 tax returns for an audit?
Math Essentials - How many ways can an IRS auditor select 4 of 9 tax returns for...
Math - How many ways can an IRS auditor select 3 of 11 tax returns for an audit...
statistics - how many ways can an IRS auditor select 5 of 12 tax returns for an ...
math - I have a question about the formula for this problem:How many ways can an...
Research &Evaluation - Need help on the following question...Please How many...
Math - . An IRS auditor randomly selects 3 tax returns from 59 returns of which ...
Statistics - An IRS auditor randomly selects 3 tax returns from 59 returns of ...
statistics - i have a test tomorrow so i need to know how to do this problem. ...
For Further Reading