Posted by **Anonymous** on Saturday, December 5, 2009 at 6:55pm.

A bucket of mass 1.70 kg is whirled in a vertical circle of radius 1.50 m. At the lowest point of its motion the tension in the rope supporting the bucket is 20.0 N.

1) Find the speed of the bucket.

2) How fast must the bucket move at the top of the circle so that the rope does not go slack?

- Physics -
**bobpursley**, Saturday, December 5, 2009 at 7:15pm
at the lowest point, tension= mg+v^2/r

solve for velocity

At the top, tension= v^2/r-mg

when tension is zero, the rope is slack, solve for velocity.

- Physics -
**Anonymous**, Sunday, October 16, 2011 at 8:15pm
m=t^a2

- Physics -
**Kyle**, Thursday, November 1, 2012 at 12:40am
bobpursley forgot to put the second mass in the equation.

whenever there is a v^2/r , remember to multiply it by mass.

tension[low] = mg + (v^2/r * m)

tension[high] = (v^2/r * m) - mg

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