How many ways can 8 people line up for play tickets?

8x7x6x....x2x1 or 8! = 40320

40,320

To find the number of ways 8 people can line up for play tickets, we can use the concept of permutations.

In this case, since we want to line up all 8 people, we are looking for arrangements, or permutations, of all the people.

The number of permutations can be calculated using the formula for permutations of n objects, which is n factorial (n!).

Therefore, the number of ways 8 people can line up is calculated as:

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320

So, there are 40,320 ways that 8 people can line up for play tickets.

To find the number of ways 8 people can line up for play tickets, we can use the concept of permutations.

A permutation is an arrangement of objects in a specific order. In this case, we want to find the number of ways to arrange the 8 people in line, which means the order matters.

The formula to calculate permutations is nPr = n! / (n - r)!, where n is the total number of objects and r is the number of objects you want to arrange.

In this case, n = 8 (as there are 8 people) and r = 8 (as we want to arrange all 8 people).

Using the formula, we get:

8P8 = 8! / (8 - 8)!
= 8! / 0!

Now, 0! (read as "0 factorial") is equal to 1 by convention. So we can simplify the expression:

8! / 1 = 8!

The exclamation mark (!) denotes the factorial of a number, which means multiplying all positive integers up to that number.

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
= 40320

Therefore, there are 40,320 ways for 8 people to line up for play tickets.