Posted by **james** on Thursday, December 3, 2009 at 11:09pm.

at 25.0m below the surface of the sea (density=1.025kg/m^3), where the temperature is 5.00C, a diver exhales an air bubble having a volume of 1.00cm^3. If the surface temperature of the sea is 20.0C, what is the volume of the bubble just before it breaks the surface?

- physics -
**drwls**, Friday, December 4, 2009 at 12:46am
Your sea density is incorrect. It is 1.025*10^3 kg/m^3

First calculate the pressure at 25 m depth, making sure that you add atmospheric pressure Po to (density)*g*(depth).

P(25 m) = 1.01*10^5 + (1.025*10^3)(9.81)*25.0 = 1.01*10^5 + 2.51*10^5 = 3.52*10^5

Prssure at 25 m depth is about 3.5 times larger than at the surface.

The ratio of bubble volume at the surface to the volume at 25 m is

[T(surface)/T(25m)]*[P(25m)/P(surface)]

=(293/278)*(3.5)

Check my numbers.

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