three dogs play tug-of-war with a chew toy. Each dog pulls with a force that is horizontal with the ground. Determine the net force acting on the chew toy and the acceleration of the chew toy if its mass is 325g. (ignore friction and gravity)

Dog 1 pull: 48.2N at 215 degrees
Dog 2 pull: 80.9N at 105 degrees
Dog 3 pull: 2.13N at 20 degrees

How do I solve for this?

To solve this problem, we need to break down each force vector into its horizontal and vertical components.

First, let's convert the mass of the chew toy from grams to kilograms. Since 1 kilogram is equal to 1000 grams, the mass of the chew toy is 325g / 1000 = 0.325 kg.

Next, let's break down the force vectors into their horizontal and vertical components using trigonometry:

For Dog 1:
Horizontal component = 48.2N * cos(215 degrees)
Vertical component = 48.2N * sin(215 degrees)

For Dog 2:
Horizontal component = 80.9N * cos(105 degrees)
Vertical component = 80.9N * sin(105 degrees)

For Dog 3:
Horizontal component = 2.13N * cos(20 degrees)
Vertical component = 2.13N * sin(20 degrees)

Now, let's add up the horizontal and vertical components separately to find the net force in each direction:

Net horizontal force = Sum of the horizontal components of all the dogs
Net vertical force = Sum of the vertical components of all the dogs

Finally, using Newton's second law (F = ma), we can determine the acceleration of the chew toy:

acceleration = net force / mass

So, to summarize the steps to solve this problem:
1. Convert the mass of the chew toy from grams to kilograms.
2. Break down each force vector into horizontal and vertical components.
3. Add up the horizontal and vertical components separately to find the net force in each direction.
4. Use Newton's second law to determine the acceleration of the chew toy.