Posted by Sasami on Thursday, December 3, 2009 at 12:23am.
(a) You want to heat the water
delta T = 100-21.6 = 78.4 degrees.
The energy needed is
Q = C M *delta T
= 4.19*280*78.4 = 91,980 joules
Power*Time = 91,980
Time (in seconds) = 91,980/293 = 314 s
Convert that to minutes.
(b) After that length of time, additional heat added is used to vaporize. In 20 minutes, the added heat is 1200 seconds * 293 J/s = 351,600 J.
Divide that by the heat of vaporization to get the number of grams of water vaporized. Subtract that from 280 g to get the number of grams left.
Thank you Dr. DRWLS
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