Posted by **Arianne** on Wednesday, December 2, 2009 at 9:32pm.

An object mass 1,448 g is attached to a spring with spring constant k = 815 N/m. The object is then displaced by a distance d from the equilibrium position and is released. Shortly after, it passes with speed v = 6.4 m/s through the equilibrium position. By what distance d was the object initially displaced?

i am extremely confused on this question..any help is greatly appreciated!!!

- physics -
**bobpursley**, Wednesday, December 2, 2009 at 9:33pm
The initial PE was 1/2 kx^2

the equilibrium KE is equal to that

so, 1/2 m 6.4^2=1/2 815*d

put in 1.448kg for m, and solve for d.

- physics -
**Karina**, Wednesday, December 2, 2009 at 11:00pm
use v=sqrt 2* Etotal/m

solve for Etotal

then use Bernoulli's equation and solve for k

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