Post a New Question

Physics

posted by on .

Alcohol flows smoothly through a horizontal pipe that tapers in cross-sectional area from A1 = 41.9 cm2 to A2= A1/3. The pressure difference Äp between the wide and the narrow sections of the pipe is 11.1 kPa. What is the volume flow rate ÄV/Ät of the alcohol? The density of the alcohol is ñ = 838 kg/m3. Hint: Treat as an ideal fluid. You will need both the conservation of mass properties and the conservation of energy properties.


i currently have..

V1=[V2(0.1397m^2)]/(o.419m^2)

not sure how to apply the conservation of energy properties..any help is greatly appreciated.

  • Physics - ,

    I would use bernoulli's equation.

  • Physics - ,

    Sub v1 into bernoulli's law and solve for v2.
    A2v2 = volume rate flow
    A2 = 1/3 A1

    (Do not worry about (-)ve sign

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question