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Posted by on Wednesday, December 2, 2009 at 7:52pm.

At what projection angle will the range of a projectile equal to 6 times its maximum height?

I know its easy but ive been absent and missed class!

  • physics - , Wednesday, December 2, 2009 at 8:03pm

    range=VcosTheta*time
    height=VsinTheta*time-4.9t^2
    or
    max height occurs when Vv=0
    Vvf=0=VsinTheta-9.8t
    solve for t.
    then put it in
    hmax=VsinTheta*t-4.9t^2
    solve for max height
    Then, multiply it by six, and set it equal to VcosTheta*2*time (twice the time to the max height).

    Prepare yourself for messy algebra.

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