Posted by tim on Wednesday, December 2, 2009 at 7:52pm.
At what projection angle will the range of a projectile equal to 6 times its maximum height?
I know its easy but ive been absent and missed class!

physics  bobpursley, Wednesday, December 2, 2009 at 8:03pm
range=VcosTheta*time
height=VsinTheta*time4.9t^2
or
max height occurs when Vv=0
Vvf=0=VsinTheta9.8t
solve for t.
then put it in
hmax=VsinTheta*t4.9t^2
solve for max height
Then, multiply it by six, and set it equal to VcosTheta*2*time (twice the time to the max height).
Prepare yourself for messy algebra.
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