Posted by **tim** on Wednesday, December 2, 2009 at 7:52pm.

At what projection angle will the range of a projectile equal to 6 times its maximum height?

I know its easy but ive been absent and missed class!

- physics -
**bobpursley**, Wednesday, December 2, 2009 at 8:03pm
range=VcosTheta*time

height=VsinTheta*time-4.9t^2

or

max height occurs when Vv=0

Vvf=0=VsinTheta-9.8t

solve for t.

then put it in

hmax=VsinTheta*t-4.9t^2

solve for max height

Then, multiply it by six, and set it equal to VcosTheta*2*time (twice the time to the max height).

Prepare yourself for messy algebra.

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