Posted by Hope on Wednesday, December 2, 2009 at 6:15am.
A 1.6 kg particle moving along the xaxis experiences the force shown in the figure. The particle's velocity is 4.2 m/s at x = 0 m.
The figure or graph has F (N) along the y axis and velocity along the x axis. A diagonal line drops from positive 10 force to 10 force from 0 cm to 4 cm. and crosses the x axis at 2 cm.
What is its velocity at 2 cm and 4 cm?
What formula do I need to use?
physics  drwls, Tuesday, December 1, 2009 at 6:58pm
Integrate F dx from 0 to 0.02 m to get the change in kinetic energy (KE) at 2 cm. Use the new value of the KE to get the new velocity. Then do it again for 0.02 to 0.04 m. The KE will decrease, since the force on the particle is in the opposite direction to motion over that interval.
physics  Hope, Tuesday, December 1, 2009 at 10:20pm
Please explain to me how to integrateI am unsure exactly what this means in this problem
Thanks

physics  bobpursley, Wednesday, December 2, 2009 at 8:38am
Ok, integrate is a calculus term. Here is the algebra way.
You know f(x)*x is the energy. But f(x)*x is the area under the f(x) line. So use your geometry to find the area under the f(x) line first at x=.02m, then x=.04 m.
That area is the energy gained.
KEfinal=keoriginal+ energy gained.
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