Posted by **kobe** on Tuesday, December 1, 2009 at 7:29pm.

prove that the following function is differentiable at x=0 using first principles:

f(x)= e^x when x<0

x=1 when x>0 or x=0

also is f(x) differntiable for all real x?

Friday

March 24, 2017
Posted by **kobe** on Tuesday, December 1, 2009 at 7:29pm.

prove that the following function is differentiable at x=0 using first principles:

f(x)= e^x when x<0

x=1 when x>0 or x=0

also is f(x) differntiable for all real x?

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