Posted by **Hope** on Tuesday, December 1, 2009 at 6:36pm.

A 1.6 kg particle moving along the x-axis experiences the force shown in the figure. The particle's velocity is 4.2 m/s at x = 0 m.

The figure or graph has F (N) along the y axis and velocity along the x axis. A diagonal line drops from positive 10 force to -10 force from 0 cm to 4 cm. and crosses the x axis at 2 cm.

What is its velocity at 2 cm and 4 cm?

What formula do I need to use?

- physics -
**drwls**, Tuesday, December 1, 2009 at 6:58pm
Integrate F dx from 0 to 0.02 m to get the change in kinetic energy (KE) at 2 cm. Use the new value of the KE to get the new velocity. Then do it again for 0.02 to 0.04 m. The KE will decrease, since the force on the particle is in the opposite direction to motion over that interval.

- physics -
**Hope**, Tuesday, December 1, 2009 at 10:20pm
Please explain to me how to integrate-I am unsure exactly what this means in this problem

Thanks

- physics -
**Peace**, Monday, October 24, 2011 at 7:01pm
Find the area under the line within each interval

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