Posted by **Jake** on Tuesday, December 1, 2009 at 12:34am.

A transverse wave on a string is described by the following equation.

y(x, t) = (0.35 m) sin[(1.25 rad/m)x + (92.8 rad/s)t]

Consider the element of the string at x = 0.

(a) What is the time interval between the first two instants when this element has a position of y = 0.303 m?

(b) What distance does the wave travel during this time interval?

- physics -
**drwls**, Tuesday, December 1, 2009 at 8:26am
The sine term must be 0.8657 if y(x,t) = 0.303. That happens at 1.0466 radians and at pi - 1.0466, or 2.0950 radians.

At x = 0, that means 92.8 t = 1.0466 or 2.0950

t = 11.3 msec or 22.6 msec

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