Posted by gianina on Monday, November 30, 2009 at 11:42pm.
Solve by eliminating possibilities. You have to distribute 88 students equally among an even number of tables. There could be 44 tables with 2 each, or 22 with 4 each, or 11 with 8 each, or 8 with 11 each, etc. One choice is more likely (22 with 4) because that is a more reasonable table size.
There is several possible solutions, and for that reason this is not a very good question for teaching math.
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