Posted by Aaron on Monday, November 30, 2009 at 10:28pm.
Let x be the distance between P and a point on the north bank directly opposite to the tanks.
The length of the pipe under water,
L1(x) = √(2²+x²).
The length of the pipe on land,
L2(x) = 3-x
Cost of laying the pipes,
C(x) = 600000 L1(x) + 300000 L2(x)
Differentiate C(x) with respect to x and equate the derivative to zero.
Solve for x.
The distance from the refinery to P is (3-x).
I get about 1.8 km.
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