An ideal gas in a container is at a temperature of 76.3°C. What is the average translational kinetic energy of a gas molecule in the container?
_________J
To find the average translational kinetic energy of a gas molecule in the container, we can use the equation:
K = (3/2) * k * T
Where:
K is the average translational kinetic energy
k is the Boltzmann constant (k = 1.380649 × 10^-23 J/K)
T is the temperature in Kelvin (K)
First, we need to convert the given temperature from Celsius to Kelvin. The relationship between Celsius and Kelvin is:
T(K) = T(°C) + 273.15
So, let's calculate the temperature in Kelvin:
T(K) = 76.3°C + 273.15 = 349.45 K
Now we can substitute the values into the equation:
K = (3/2) * (1.380649 × 10^-23 J/K) * (349.45 K)
Calculating this expression gives us the average translational kinetic energy of a gas molecule in the container.