The mass of a carbon atom is 2 x 10 ^ -26. What is the kinetic energy of a carbon atom moving with a speed of 500 m/s?
What is the formula I would need?
KE=1/2 m v^2
Second question says two carbon atoms are joined by a spring-like carbon-carbon bond. The potential energy stored in the bond has the value you calculated from first question if the bond is stretched 0.050 nm. What is the bond's spring constant? What is the formula for this?
Second question says two carbon atoms are joined by a spring-like carbon-carbon bond. The potential energy stored in the bond has the value calculated from first question if the bond is stretched 0.050 nm. What is the bond's spring constant? What is the formula for this?
To calculate the kinetic energy of an object, you can use the formula:
Kinetic Energy (KE) = 1/2 * mass * velocity^2
In this case, the mass of the carbon atom is given as 2 x 10^ -26 kg, and the speed as 500 m/s.
So, substituting the given values into the formula, we have:
KE = 1/2 * (2 x 10^ -26 kg) * (500 m/s)^2
Before proceeding with the calculation, we need to convert the mass from scientific notation to decimal form.
2 x 10^ -26 kg = 0.0000000000000000000000002 kg
Now, we can proceed with the calculation:
KE = 1/2 * (0.0000000000000000000000002 kg) * (500 m/s)^2
Note: We square the velocity value since the kinetic energy is proportional to the square of the velocity.
KE = 1/2 * (0.0000000000000000000000002 kg) * (250000 m^2/s^2)
KE = 0.0000000000000000000000001 kg * m^2/s^2
Finally, we can express the result in scientific notation:
KE = 1 x 10^ -28 kg * m^2/s^2
Hence, the kinetic energy of the carbon atom moving with a speed of 500 m/s is 1 x 10^ -28 kg * m^2/s^2.