how do you solve quadratic equations by finding square roots
i have no clue how to do this. I have fallen behind in my math class because my teacher is horrible. I need to learn this to understand everything in the section in the section. I beg someboody to answer this question. i don't want any replys like figure it out yourself or coments like ms. sue has ben posting as `answers'.Pleeaseeeeee!
<3 converse
To solve quadratic equations by finding square roots, follow these steps:
1. Write the quadratic equation in the standard form: ax^2 + bx + c = 0, where a, b, and c are constants.
2. If the coefficient of the x^2 term (a) is not 1, divide the entire equation by a to make it easier to work with.
3. Move the constant term (c) to the other side of the equation, so that the equation becomes ax^2 + bx = -c.
4. Take the square root of both sides of the equation. This will help eliminate the "squared" term.
5. Now, you will have two cases to consider: positive and negative square roots. Since the square root of a number can be either positive or negative, you will get two possible solutions.
6. Solve for x in each case by isolating the variable on one side of the equation.
For example, let's solve the quadratic equation x^2 - 9 = 0:
1. The equation is already in the standard form.
2. Since the coefficient of x^2 is 1, we can skip this step.
3. Move the constant term to the other side: x^2 = 9.
4. Take the square root of both sides: √(x^2) = ±√9.
5. You get two possibilities: x = ±3.
6. So, the solutions to the quadratic equation x^2 - 9 = 0 are x = 3 and x = -3.
Remember, if the quadratic equation is not in standard form, you need to rearrange it before following these steps.
I doubt your teacher is horrible, I suspect you need to look in the mirror.
The answer depends on the equation
if it is like this....
x^2-25=0
x^2=25
take the square root of each side:
x=+-5