Friday

March 27, 2015

March 27, 2015

Posted by **Andy** on Monday, November 30, 2009 at 4:28pm.

Im using the equation pv2^2(A2^2-A1^2)/2A1^2 and get (1000)(3)^2(1.8^2-3^20/(2(3)^2) and get -2880 Pa but I'm getting wrong? Thanks

- physics -
**bobpursley**, Monday, November 30, 2009 at 4:41pmI have no idea what you are doing.

pstatic1+rho*V1^2/2=pstatic2+rhoV2^2/2

you want pstatic1-pstatic1

So you need V2: Using the law of continuity,

Area1*V1=area2*V2 or V2=V1(1.8/3.0)^2

or V2=1.08m/s

pressure difference=rho(V2^2-V1^2)/2

=1000*(1.08^2-3^3)/2

check my thinking

**Answer this Question**

**Related Questions**

physics - A horizontal pipe 17.00 cm in diameter has a smooth reduction to a ...

Physics - A horizontal pipe, 10 cm in diameter, has a smooth reduction to a pipe...

physics - A horizontal pipe 17.00 cm in diameter has a smooth reduction to a ...

algebra - A pipe manufacturer makes pipes of four different sizes. The diameter ...

algebra - A pipe manufacturer makes pipes of four different sizes. The diameter ...

Physics - Water flows under pressure from one pipe into a second pipe having ...

physics - Water flows in a cylindrical, horizontal pipe. As the pipe widens to ...

Physics - A liquid of density 1.23 × 103 kg/m3 flows steadily through a pipe of ...

physics - A large water tank has an inlet pipe and an outlet pipe. The inlet ...

Physics - A horizontal pipe contains water at a pressure of 120kPa flowing with ...