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July 31, 2014

July 31, 2014

Posted by **Ed** on Monday, November 30, 2009 at 2:15am.

____ rad/s2

- Physics -
**drwls**, Monday, November 30, 2009 at 6:41amThe wheel is decelerating in angular velocity. If the drops rise a distance H, they were released with a velocity V such that

V = sqrt(2gH)

For turn 1, V1 = 3.255 m/s

Fot turn 2, V2 = 3.037 m/s

The average wheel velocity between the release of the two drops is

Vav = 3.146 m/s.

The elapsed time between release of the two drops is

T = 2 pi R/ Vav = 0.88 s

The angular acceleration rate is

(1/R)(V2 - V1)/T = __ rad/s

- Physics -
**Ed**, Monday, November 30, 2009 at 2:38pmThank you for helping! got the answer correct (:

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