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December 18, 2014

December 18, 2014

Posted by **Liz** on Monday, November 30, 2009 at 12:24am.

- Algebra -
**drwls**, Monday, November 30, 2009 at 6:48amThe standard quadratic equation form is

ax^2 + bx + c = 0

and your equation is, if your (2) is supposed to be an exponent,

12x^2 -15x = 0

Therefore a = 12, b = -15 and c = 0

You have reduced your equaion to

4x^2 -5x = 0,

so using a=4, b=-5 and c=0 would give you the same results for x.

You should get x = 0 and x = 5/4 as the solutions, using the quadratic equation

x = [-b +/-sqrt(b^2 -4ac)]/(2a)

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