Posted by Shawn on Sunday, November 29, 2009 at 9:56pm.
What is the probability that a number chosen at random from the range 1,000,000,000 to 9,999,999,999 inclusive will contain ten different digits? Round your answer to the nearest millionth

Math  MathMate, Sunday, November 29, 2009 at 10:00pm
The number of ways the 10 distinct digits can form distinct numbers is given by
10!.
So the probability is 10! divided by the number of possible outcomes.

Math  Damon, Sunday, November 29, 2009 at 10:10pm
The first digit on the right can be any number from 0 to 9 so ten choices
1/10 so far
the second digit (tens place) can be one of 9
1/10 * 1/9
the third can be one of 8 remaining
1/10 * 1/9 * 1/8
etc
get the picture?

Math  Shawn, Sunday, November 29, 2009 at 10:19pm
So after i do all that should i get one whole number

Math  Damon, Sunday, November 29, 2009 at 10:42pm
No, you will not get a whole number
a probability is a number between 0 and 1
1/10! which is about .00000027
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