Posted by **Shawn** on Sunday, November 29, 2009 at 9:56pm.

What is the probability that a number chosen at random from the range 1,000,000,000 to 9,999,999,999 inclusive will contain ten different digits? Round your answer to the nearest millionth

- Math -
**MathMate**, Sunday, November 29, 2009 at 10:00pm
The number of ways the 10 distinct digits can form distinct numbers is given by

10!.

So the probability is 10! divided by the number of possible outcomes.

- Math -
**Damon**, Sunday, November 29, 2009 at 10:10pm
The first digit on the right can be any number from 0 to 9 so ten choices

1/10 so far

the second digit (tens place) can be one of 9

1/10 * 1/9

the third can be one of 8 remaining

1/10 * 1/9 * 1/8

etc

get the picture?

- Math -
**Shawn**, Sunday, November 29, 2009 at 10:19pm
So after i do all that should i get one whole number

- Math -
**Damon**, Sunday, November 29, 2009 at 10:42pm
No, you will not get a whole number

a probability is a number between 0 and 1

1/10! which is about .00000027

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