Posted by A.J. on Sunday, November 29, 2009 at 9:16pm.
yes. S = P (1+r)^n
100 = 20 (1+r)^18
(1+r)^18 = 5
18 log (1+r) = log 5
using base 10 logs
18 log(1+r) = .699
log(1+r) = .0388
take antilog
1+r = 1.0935
r = .0935
times 100 = 9.35 %
Thanks for the help but I still don't understand. What does log and antilog stand for?
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