Posted by ann on Sunday, November 29, 2009 at 4:11pm.
You would assume the side of the square (base or top) to be x (feet).
The height can be expressed in terms of x and the volume. (V=L*W*H=x²*H)
You would then express the sum of the costs, C, made up of
1. the cost of the base = area of base * unit cost of base,
2. the cost of the sides and
3. the cost of the top.
Now differentiate C(x) with respect to x and equate C'(x)=0. Solve for x.
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