Sunday

December 28, 2014

December 28, 2014

Posted by **ann** on Sunday, November 29, 2009 at 4:11pm.

- Calculus -
**MathMate**, Sunday, November 29, 2009 at 4:28pmYou would assume the side of the square (base or top) to be x (feet).

The height can be expressed in terms of x and the volume. (V=L*W*H=x²*H)

You would then express the sum of the costs, C, made up of

1. the cost of the base = area of base * unit cost of base,

2. the cost of the sides and

3. the cost of the top.

Now differentiate C(x) with respect to x and equate C'(x)=0. Solve for x.

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