Posted by **alison** on Saturday, November 28, 2009 at 9:59pm.

you are designing a 1000-cm^3 right circular cylindrical can whose manufacture will take waste into account. There is no waste in cutting the aluminum for the side, but the top and bottom of radius r will be cut from squares that measure 2r units on a side. The total amount of aluminum used up by the can will therefore be: A=8r^2 +2(pi)(r)(h)

What is the ratio of h to r for the most economical can?

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