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AP Chemistry

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An aqueous antifreeze is 40.0% ethylene glycol (C2H6O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol.

  • AP Chemistry - ,

    A long problem here. You can help by telling me what you don't understand about it before I spent half the night working all of it out in detail.
    I'll get you started.
    40% by mass means 40 g ethylene glycol + 60 g water.
    Convert 40 g ethylene glycol to moles. moles = grams/molar mass.
    molality = moles/kg solvent(60 g water = 0.060 kg).
    For molarity, use mols/L of solution.
    Look up mole fraction.
    That's Xeth gly = (neth gly/total moles.

  • AP Chemistry - ,

    6.77M

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