Find an equation of the line having the given slope and containg the given point m=8/9,(4,-7)
The equation of the line is y=?
Please help me with this. Thanks
See this answer.
http://www.jiskha.com/display.cgi?id=1259424016
Into the form y = mx + b, substitute m = 8/9
That leave you with
y = (8/9)x + b
To get b, require that y = -7 when x = 4.
-7 = (8/9)*4 + b
b = -7 -32/9 = -95/9
y = (8/9)x -(95/9), or [8x -95)]/9
Could you possibly help me withe the rest of the problems posted? I'm getting desperate lol
To find the equation of a line, you can use the slope-intercept form, which is given by:
y = mx + b
where:
- y and x are the coordinates of a point on the line.
- m is the slope of the line.
- b is the y-intercept of the line.
In this case, you are given the slope (m = 8/9) and a point on the line (4, -7). To find the equation, we need to substitute these values into the slope-intercept form and solve for b.
Substituting the given point (x, y) = (4, -7) and the slope m = 8/9 into the slope-intercept form, we get:
-7 = (8/9)(4) + b
To simplify, we multiply the slope (8/9) by 4:
-7 = 32/9 + b
To solve for b, we need to isolate it on one side. Subtracting 32/9 from both sides gives:
-7 - 32/9 = b
To simplify further, we can convert -7 to a fraction with a common denominator of 9:
-63/9 - 32/9 = b
Now combining the fractions:
- 95/9 = b
So, the y-intercept of the line is b = -95/9.
Now that we have the slope (m = 8/9) and the y-intercept (b = -95/9), we can write the equation of the line:
y = (8/9)x - 95/9
Therefore, the equation of the line is y = (8/9)x - 95/9.