Algebra
posted by Leyla on .
I think the vertex from 1/4t(t2)^2 is 2,0. But I'm not sure how to get the other vertices, as well as the x intercepts. Can you explain, please? THanks!

is the t(t2)^2 in the denominator? Or only the 4? I can't tell when you write it like that.
Since your independent variable is t, I assume you want tintercepts. To get t intercepts (where y = 0), set the equation equal to zero and solve for the t values that are roots. 
It's (1/4)t...