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September 24, 2014

September 24, 2014

Posted by **Lilly** on Friday, November 27, 2009 at 2:24am.

- Physics -
**MathMate**, Friday, November 27, 2009 at 1:00pmThe key is to find the tangential velocities at each of the turns, v1 and v2.

The initial velocity v for an object thrown upwards will reach a height of h is related by the formula:

h=v²/2g

where g is acceleration due to gravity.

Conversely, given h, we can find v from:

v=√(2gh)

So the tangential velocities v1 and v2 can be determined from h1 and h2 (work in metres).

Since the tangential velocities v1 and v2 are known, the average tangential velocity is

va=(v1+v2)/2

The time it took to make the turn was

t=2πr/va

From angular velocity

= v/r radians/sec

We can determine angular acceleration, a

=(v2-v1)/r/t

Solve for a. I get about 1.4 rad./s.

Check my calculations.

- Physics -
**Lilly**, Saturday, November 28, 2009 at 1:41amI also got about 1.4 rad/s, but is the answer negative? -1.4 rad/s?

Thanks!

- Physics -
**MathMate**, Saturday, November 28, 2009 at 8:24amAngular acceleration is defined as (ω2-ω1)/time, since ω2 is bigger, evidenced by the fact that the droplet shoots higher in the second turn than the first, the value calculated

*should*be positive.

If you got a negative answer according to the equations, it's time to give a thorough check.

- Physics -
**Lilly**, Saturday, November 28, 2009 at 1:13pmNo, I thought the answer was positive too, but when I entered it in, a message popped up and said "Your anwer has the wrong sign". That's why I asked.

- Physics -
**MathMate**, Saturday, November 28, 2009 at 4:55pmUnless the heights of the drops have been inverted, I would be tempted to say that there is an error in the answer.

Double check the order of the heights of the droplets, i.e. 0.44 m followed by 0.58 m on the next turn. If that's the case, you could report your findings to your teachers so you don't get penalized.

After all, the people who put the answers on the computer are human, so mistakes are possible.

- Physic -
**Ed**, Saturday, November 28, 2009 at 7:34pmI have a question similar to this but I don't know what you did in each step. Could you plug in all the numbers step by step.

- Physics -
**MathMate**, Saturday, November 28, 2009 at 8:28pmI suggest you post a new question and it will get a personalized answer.

Otherwise, you can post what you get and if you don't get the right answer, we'll help you find the problem.

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