"a stone tied at the end of a 0.71 m long string"
"4 revolutions per second"
Tangential speed, v0
"The stone is 0.93 m above the ground"
Distance above ground, h
"an angle of 54 degrees above the horizontal"
Vertical component of initial velocity, vv
Let t=time it takes to hit ground,
-0.93 = vv*t+(1/2)(-9.8)t²
Solve for t.
I get -0.051 sec. or 4 sec. approx.
We reject -0.051 because t>0.
I tried doing the problem your way, but I got confused at the end.
For the equation S = w*t + (1/2)(-9.8)t**2, what was the value of w?
When I tried using w = v0 (17.844m/s), I got the same answers as yours
But when I tried using w = v0sin54 (14.4363m/s), I got different answers. I'm not sure which way is right. I'm leaning toward the latter one.
You're quite right.
I have calculated for 5 revolutions per second. That is why they don't match your answers, which are on the right track.
I get now -0.06 and 3 seconds, and -0.06 is to be rejected.
What do you get for your answers?
Sorry for the inconvenience.
Yes, I also got -0.06 and 3.00 seconds, so obviously the answer is 3.00 seconds.
Thanks for your help :)
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