A stone is dropped into a river from a bridge 41.7 m above the water. Another stone is thrown vertically down 1.87 s after the first is dropped. Both stones strike the water at the same time. What is the initial speed of the second stone?
physics - MathMate, Thursday, November 26, 2009 at 11:14pm
S=41.7 m, u=0, g=9.8 m/s²
Solve for t.
S=v0(t-1.87) - (1/2)g(t-1.87)²
Solve for v0.