Physics need help
posted by Tam on .
A guitar string is struck and found have a frequency of 2048Hz. If both tension and length are doubled, what is the new frequency of the string?

The fundamental frequency (first harmonic) of a plucked string is given by
f=(1/2L)√(T/ρ)
where L=length, T= tension and ρ=mass/unit length
So we see that the frequency is inversely proportional to the length, and proportion to the squareroot of the tension.
If both of them are doubled, then new frequency, f1 is can be obtained by :
f1=f*(1/2)*&radic(2)
=f/&radic(2)
=2048/1.414213562
=1448 Hz approximately