Posted by Desire on Wednesday, November 25, 2009 at 12:02pm.
The probability of being within Z = ±2 for a normal distribution always approximates 95%. However, what you might be seeking is the high and low values that cut off that proportion.
Standard error of the mean (SE) = standard deviation/square root of n
Z = (raw score - mean)/SE
±2 = (raw score - 100)/SE
Use the four SEs to find the raw score (±).
I hope this helps.
I don't understand how to get the answer using the formula.
For n = 100:
Lower limit: 100 - 2*16/sqrt(100) = 96.8
Upper limit: 100 + 2*16/sqrt(100) = 103.2
I can't get the answer for the other ones
Can you please help me solve for N
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